java在忽略数字的同时移动字符串中的字符

Question

我需要创建一个输入为字符串的方法，例如：asd321tre2。 输出应为：eas321dtr2。字符应向前移动一个位置，但数字应保持在同一位置。 输入：字符串s1=“abc23sd23”； 输出：String s2=“dab23cs23”

public static String revertTheString (String s) {
    String helper = s.replaceAll("\\d", "");
    helper = helper.substring(helper.length()-1) + helper.substring(0, helper.length()-1);
    int start = 0, end = 0;

    StringBuilder revert = new StringBuilder(s);

    for (int i = 0; i< s.length(); i++) {
        if(Character.isDigit(s.charAt(i))){
            end = i;
            revert = revert.replace(start, end, helper.substring(start, end));
            while(Character.isDigit(s.charAt(i))){
                i++;
                start = i;
            }
        }
    }
    return revert.toString();
}

Answer 1

您可以尝试交换第一个和最后一个字符值，如下所示

====================================================================================

    String s = "asd321tre2";
    char[] charr = s.toCharArray();
    int end = 0;

    for (int i = s.length(); i <= 0; i ) {
        if (Character.isLetter(charr[i])) {
            end = i;

        }
    }
    String output = charReplace(end, charr);
}

private static String charReplace(int end, char[] ch) {

    for (int i = 0; i < ch.length; i++) {
        if (Character.isLetter(ch[i])) {
            char tmp = ch[i];
            ch[i] = ch[end];
            ch[end] = tmp;
        }
    }
    String output = String.valueOf(ch);
    return output;

}

====================================================================================

希望这有帮助

谢谢， 帕提班